Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 6 (Q.No. 24)
24.
The density of a liquid is 1500 kg/m3. Its value in gin/litre will be equal to
Discussion:
4 comments Page 1 of 1.
Ramsajan said:
2 years ago
1500kg/m^3 = 1500 * 1000/1000gm/L then 1500 gm/L.
Pawan Kumar Sharma said:
2 years ago
@Gaurav.
I think it may be g/lt.
I think it may be g/lt.
Gaurav said:
8 years ago
1kg =1.6666gin,
Than 1500kg =2500gin,
How ans will be 1500?
Than 1500kg =2500gin,
How ans will be 1500?
Fidis said:
8 years ago
1500kg/m3 * 1000g/kg * 1m3/1000lit = 1500g/lit.
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