Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 4 (Q.No. 20)
20.
A gaseous mixture contains 14 kg of N2, 16 kg of O2 and 17 kg of NH3. The mole fraction of oxygen is
Discussion:
8 comments Page 1 of 1.
Ankur varma said:
10 years ago
Yes the correct answer is 0.25 only, which is not given in the option only.
@Rishi they have asked for mole fraction of oxygen and not the "MASS FRACTION". If they could have ask for mass fraction they 0.34 is the correct answer.
@Rishi they have asked for mole fraction of oxygen and not the "MASS FRACTION". If they could have ask for mass fraction they 0.34 is the correct answer.
TANMAY SHAH said:
2 years ago
Mass [gm] = M.W. × Moles.
By putting the given values in above equation we get the number of moles of,
N2 = 500 moles,
O2 = 500 moles,
NH3 = 1000 moles,
So, we get the mole fraction of O2 is 0.25.
By putting the given values in above equation we get the number of moles of,
N2 = 500 moles,
O2 = 500 moles,
NH3 = 1000 moles,
So, we get the mole fraction of O2 is 0.25.
Gabriel Rosado said:
1 decade ago
I think something is wrong.
Mass fraction of O2= 16/(14+16+17) = 0.34.
Mole fraction of O2= (16/32)/(14/28+16/32+17/17) = 0.25.
Right?
Mass fraction of O2= 16/(14+16+17) = 0.34.
Mole fraction of O2= (16/32)/(14/28+16/32+17/17) = 0.25.
Right?
(1)
Rishi said:
1 decade ago
Mole fraction of O2=16/14+16+17=0. 33.
(2)
Deven sonj said:
9 years ago
The correct answer should be 0.25.
(1)
Deepak said:
4 years ago
.25 is the correct answer.
(1)
Hanadi said:
8 years ago
0.25 is correct answer.
(1)
Hatdu said:
4 years ago
Explain the answer.
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