Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 1 (Q.No. 20)
20.
Equal masses of CH4 and H2 are mixed in an empty container. The partial pressure of hydrogen in this container expressed as the fraction of total pressure is
Discussion:
11 comments Page 1 of 2.
Amjed Qarahgouli said:
3 years ago
Assume 100g of H2 and 100g of CH4.
Moles of H2=m/Mwt = 100/2 = 50 moles,
Moles ofCH4=100/16 = 6.25 moles.
Total moles = 56.25 moles.
mole fraction of H2 y = 50/56.25 = 0.8 = 8/9.
Dalton's low p = y*P.
At atmospheric pressuer 1atm.
p=8/9 * 1 = 8/9 atm.
Moles of H2=m/Mwt = 100/2 = 50 moles,
Moles ofCH4=100/16 = 6.25 moles.
Total moles = 56.25 moles.
mole fraction of H2 y = 50/56.25 = 0.8 = 8/9.
Dalton's low p = y*P.
At atmospheric pressuer 1atm.
p=8/9 * 1 = 8/9 atm.
(5)
Shiraz said:
5 years ago
Suppose equal mass is considered to be 16 g each, so moles me hydrogen is 8 and methane is 1, total moles are 8+1=9, mole fraction of hydrogen is 8/9.
(1)
I.SIVAREDDY said:
1 decade ago
Given that initial mass of H2 and CH4 are equal. And take each mass as m kg initially.
Mass of H2 = m kg moles of H2 = m/2;
Mass of CH4 = m kg moles of CH4 = m/16;
Mole fraction of H2 (yH2) = (moles of H2)/(moles of H2 + moles of CH4)
(yH2) = (m/2)/(m/2+m/16) = 8/9.
Mass of H2 = m kg moles of H2 = m/2;
Mass of CH4 = m kg moles of CH4 = m/16;
Mole fraction of H2 (yH2) = (moles of H2)/(moles of H2 + moles of CH4)
(yH2) = (m/2)/(m/2+m/16) = 8/9.
Tamilselvan said:
1 decade ago
I didn't understood here the question is fraction of total pressure but you given the answer in terms of mole fraction.
Swamy said:
10 years ago
Mole is not sufficient.
Amol said:
10 years ago
Mole fraction = Pressure fraction = Volume fraction.
SHUDHAKAR MISHRA said:
9 years ago
By Henry law;
P.H2 = {X.H}P
PH2/P = X.H
Where PH2 is partial pressure of H2 and P is the total pressure of the container.
X.H is mole fraction of hydrogen.
The partial pressure of hydrogen in this container expressed as the fraction of total pressure .
P.H2 = {X.H}P
PH2/P = X.H
Where PH2 is partial pressure of H2 and P is the total pressure of the container.
X.H is mole fraction of hydrogen.
The partial pressure of hydrogen in this container expressed as the fraction of total pressure .
Ramesh vishwakarma said:
9 years ago
We take in molar form.
Azharuddin said:
5 years ago
Total Pressure * mole fraction in gas phase= partial Pressure.
Srinu said:
4 years ago
1/9 is the answer.
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