Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 6 (Q.No. 27)
27.
2 litres of nitrogen at N.T.P. weighs __________ gms.
Discussion:
4 comments Page 1 of 1.
Fids said:
8 years ago
pv=nrt.
n=mass/mwt.
so,
m=p*v*mwt/rt.
m=1*2*28/.0821*273,
m=2.5.
n=mass/mwt.
so,
m=p*v*mwt/rt.
m=1*2*28/.0821*273,
m=2.5.
(1)
G K Misra said:
7 years ago
NTP = 1 atm and 15 C = 1 atm and (15+273)K.
Pawan Kumar Sharma said:
2 years ago
NTP stands for Normal Temperature and Pressure at NTP.
Temperature is 293 K(20 degree centigrade)
Pressure is 1 atm.
PV = nRT.
n = PV/RT.
n = (1atm×2L)/(0.08206 L atm/mol×293 K) = 0.083 mol.
Weight of N2 = No. of moles × molar mass of N2.
= 0.083 × 28 = 2.33 g.
Temperature is 293 K(20 degree centigrade)
Pressure is 1 atm.
PV = nRT.
n = PV/RT.
n = (1atm×2L)/(0.08206 L atm/mol×293 K) = 0.083 mol.
Weight of N2 = No. of moles × molar mass of N2.
= 0.083 × 28 = 2.33 g.
Ramsajan said:
2 years ago
We know that at NTP
1 mole =22.4L then 2L = 2/22.4 =1/11.2 moles now moles * molecular weight = weight in gm
Then 1/11.2 * 28 = 2.5gm.
1 mole =22.4L then 2L = 2/22.4 =1/11.2 moles now moles * molecular weight = weight in gm
Then 1/11.2 * 28 = 2.5gm.
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