Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 2 (Q.No. 30)
30.
At standard conditions,
N2 + 2O2
2NO2; ΔG° = 100 kJ/mole
NO +
O2 2NO2; ΔG° = -35 kJ/mole
The standard free energy of formation of NO in kJ/mole is
N2 + 2O2
2NO2; ΔG° = 100 kJ/moleNO +
O2 2NO2; ΔG° = -35 kJ/moleThe standard free energy of formation of NO in kJ/mole is
Discussion:
3 comments Page 1 of 1.
RTCM said:
2 weeks ago
Reaction 2 is not correctly balanced. The answer should be D.
1) N2 + 2O2 = 2NO2; ΔG°(1) = 100 kJ/mole.
2) NO + 1/2 O2 = NO2; ΔG°(2) = -35 kJ/mole.
Reversing: NO2 = NO + 1/2 O2 = ; ΔG°(2) = 35 kJ/mole.
Multiplying by 2: 2NO2 = 2NO + O2 ; ΔG°(2) = 2*35 kJ/mole = 70 kJ/mole.
3) Net reaction: N2 + O2 = NO; ; ΔG° = 100 + 70 = 170 kJ/mole.
1) N2 + 2O2 = 2NO2; ΔG°(1) = 100 kJ/mole.
2) NO + 1/2 O2 = NO2; ΔG°(2) = -35 kJ/mole.
Reversing: NO2 = NO + 1/2 O2 = ; ΔG°(2) = 35 kJ/mole.
Multiplying by 2: 2NO2 = 2NO + O2 ; ΔG°(2) = 2*35 kJ/mole = 70 kJ/mole.
3) Net reaction: N2 + O2 = NO; ; ΔG° = 100 + 70 = 170 kJ/mole.
Pawan Kumar Sharma said:
1 year ago
I think it will be 65.
(1)
Umang said:
5 years ago
Can someone explain?
(1)
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