Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 1 (Q.No. 15)
15.
A sample of well water contains 140 gm/m3 Ca2+ ions and 345 gm/m3 Na+ ions. The hardness of the sample of water, expressed in terms of equivalent CaCO3 in gm/m3 is (assuming atomic masses of Ca :40, Na : 23, C : 12, O : 16)
Discussion:
4 comments Page 1 of 1.
Ganesh Gore said:
1 decade ago
Atomic mass of ca 40.
Molecular weight of caco3 is 100.
Therefore 40gms of ca = 100 gm of caco3.
Then 140gms of ca = ? gm of caco3.
By simplifying that 100*140 / 40.
Weight of caco3 = 350.
Molecular weight of caco3 is 100.
Therefore 40gms of ca = 100 gm of caco3.
Then 140gms of ca = ? gm of caco3.
By simplifying that 100*140 / 40.
Weight of caco3 = 350.
(6)
Meethi said:
5 years ago
Na don't affect the hardness,
so 1 mol ca+=1mol of caco3 by this way you can calculate.
so 1 mol ca+=1mol of caco3 by this way you can calculate.
Nithin said:
1 decade ago
Na+ ions not affecting hardness.
140 g Ca2+ equivalent to 350g CaCO3.
140 g Ca2+ equivalent to 350g CaCO3.
(1)
Kabenda said:
1 decade ago
How 140g equivalent to 350g?
(1)
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