Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 1 (Q.No. 16)
16.
Assuming that CO2 obeys perfect gas law, calculate the density of CO2 (in kg/m3) at 263°C and 2 atm.
Discussion:
7 comments Page 1 of 1.
Masereka Boniface said:
4 years ago
Ideal gas relation is expressed as PV =nRT; n= mass/Molecular weight).
So, PV= (mass/molecular weight) RT, make mass as subject, and hence derive density is mass/volume. V for volume cancels out you arrive at 2 as answer.
So, PV= (mass/molecular weight) RT, make mass as subject, and hence derive density is mass/volume. V for volume cancels out you arrive at 2 as answer.
(1)
Imelda said:
9 years ago
PV=nRT ;n=PV/RT ; P=2 atm, 22.4 L/mole, 0.08205 L-atm/mole-K; T=263+273
n= 0.98; mwCO2= 44kg/mole.
Density = mass/volume;
Mass = nMW = 0.98(44kg/mole) = 43.43 kg/mole.
Density = 43.43/ 22.4 L/mole = 1,98 kg/liter.
n= 0.98; mwCO2= 44kg/mole.
Density = mass/volume;
Mass = nMW = 0.98(44kg/mole) = 43.43 kg/mole.
Density = 43.43/ 22.4 L/mole = 1,98 kg/liter.
(4)
REMINGTON SALAYA said:
1 decade ago
Density of an Ideal Gas (D i. g.):
D i. g. = PM/RT ; P= Pressure, M = Molecular Weight, R = Gas constant, and T = temperature (absolute).
M (CO2) = 40.
D i. g. = 2(40)/(0.0821)(263+273.15) ~ = 2 g/L or 2 kg/m3.
D i. g. = PM/RT ; P= Pressure, M = Molecular Weight, R = Gas constant, and T = temperature (absolute).
M (CO2) = 40.
D i. g. = 2(40)/(0.0821)(263+273.15) ~ = 2 g/L or 2 kg/m3.
Mahbubur Rahman said:
9 years ago
PV = (g/m)RT.
Density, g/V = (PM/RT),
Here, P = 2atm, M = 44, R = 0.0821L atm/mol/k, T = (263 + 273)k.
= (2 * 44)/(0.821 * 536) = 2 gm/L= 2 kg/m^3.
Density, g/V = (PM/RT),
Here, P = 2atm, M = 44, R = 0.0821L atm/mol/k, T = (263 + 273)k.
= (2 * 44)/(0.821 * 536) = 2 gm/L= 2 kg/m^3.
(3)
Ankita davane said:
9 years ago
M(CO2) = 44 gm,
PV = nRT,
PV = (M/m) * RT,
Density = mass/vol,
= (2 * 44)/(0.8205 * (263 + 273)) = 2 kg/m^3.
PV = nRT,
PV = (M/m) * RT,
Density = mass/vol,
= (2 * 44)/(0.8205 * (263 + 273)) = 2 kg/m^3.
(1)
Barjesh said:
1 decade ago
M(CO2) = 44 gm.
= (2*1.01325*100000*0.044)/(8.314*(263+273)).
= 2 kg/m3.
= (2*1.01325*100000*0.044)/(8.314*(263+273)).
= 2 kg/m3.
(1)
Pradip said:
4 years ago
R value in atm is 0.082.
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