Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 5 (Q.No. 5)
5.
The molar composition of a gas is 10% H2, 10% O2, 30% CO2 and balance H2O. If 50% H2O condenses, the final mole percent of H2 in the gas on a dry basis will be
Discussion:
2 comments Page 1 of 1.
TANMAY SHAH said:
2 years ago
Please anybody explain the answer with a calculation.
Sunil kumar yadav said:
11 months ago
Solution:
Assuming 100mol of the Gas.
Then mole of H2 = 10,
Mole of oxygen = 10,
Mole of CO2 = 30,
Mole of H2O = 50,
Only dry gas moles = 10 + 10 + 30(H2 + O2 + CO2) = 50.
Then mole of H2 on dry gas basis10/50*100=20%
Assuming 100mol of the Gas.
Then mole of H2 = 10,
Mole of oxygen = 10,
Mole of CO2 = 30,
Mole of H2O = 50,
Only dry gas moles = 10 + 10 + 30(H2 + O2 + CO2) = 50.
Then mole of H2 on dry gas basis10/50*100=20%
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