Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 3 (Q.No. 10)
10.
In the reaction, Ca + 2H2O = Ca(OH)2 + H2 ; what volume (c.c.) of hydrogen at STP would be liberated, when 8 gm of calcium reacts with excess water ? (atomic weight of calcium = 40)
Discussion:
2 comments Page 1 of 1.
Parth said:
6 years ago
1 mol at stp = 22.4 lit.
40 grms ca gives 22.4 lit.
So 8 grms ca?
= 8*22.4/40.
= 4.48 lit.
= 4480 c.c.
40 grms ca gives 22.4 lit.
So 8 grms ca?
= 8*22.4/40.
= 4.48 lit.
= 4480 c.c.
(2)
Guruputi mohan said:
6 years ago
The answer should be D.
As per stoichiometric Eqn, 1 mole of ca is producing 1 mole of h2.
So 8gms of ca = 8/40 (mol.wt)= 0.2 gm.moles,
So h2 also produced will be 0.2 gm.moles as per the eqn,
The weight of H2 = 0.2*2 (mol.wt) = 0.4.
As per stoichiometric Eqn, 1 mole of ca is producing 1 mole of h2.
So 8gms of ca = 8/40 (mol.wt)= 0.2 gm.moles,
So h2 also produced will be 0.2 gm.moles as per the eqn,
The weight of H2 = 0.2*2 (mol.wt) = 0.4.
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