Chemical Engineering - Stoichiometry - Discussion

Discussion Forum : Stoichiometry - Section 8 (Q.No. 33)
33.
1 gm mole of an alcohol whose molecular weight is 74 contains 48 gms of carbon, 10 gms of hydrogen and 16 gms of oxygen. Its molecular formula is
C4H9OH
C3H21OH
(C2H4)2H2.OH
C2H33OH
Answer: Option
Explanation:
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Discussion:
1 comments Page 1 of 1.

Sonu said:   6 years ago
Total C atoms = 48/12 = 4.
Total O atom = 16/16 = 1.
Total H atom = 10/1 = 10.

C4H9OH.

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