Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 1 (Q.No. 29)
29.
N2 content in a urea sample was found to be only 42%. What is the actual urea content of the sample ? (molecular weight of urea = 60)
Discussion:
2 comments Page 1 of 1.
Tamilselvan said:
1 decade ago
Mol wt of urea = 60.
So 60 gm of urea contains 28 gm of nitrogen.
So % of nitrogen in 100% urea = 28/60*100.
100% urea contains 46.67% of Nitrogen.
Actual % of nitrogen is 42%.
So % of urea = 42/46.67*100.
= 90%.
So 60 gm of urea contains 28 gm of nitrogen.
So % of nitrogen in 100% urea = 28/60*100.
100% urea contains 46.67% of Nitrogen.
Actual % of nitrogen is 42%.
So % of urea = 42/46.67*100.
= 90%.
(3)
Idrees said:
1 decade ago
60 grams of urea = 2*14 grams of nitrogen.
? = 42 grams of nitrogen.
Actual content of urea is = 60*42/28=90.
Assume total content is 100.
? = 42 grams of nitrogen.
Actual content of urea is = 60*42/28=90.
Assume total content is 100.
(1)
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