Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 2 (Q.No. 40)
40.
Simultaneous doubling of the absolute temperature of a gas and reduction of its pressure to half, will result in __________ in the volume of the gas.
Discussion:
7 comments Page 1 of 1.
TANMAY SHAH said:
3 years ago
PV = nRT.
n and R are constant.
So, PV/T = constant.
So, P1V1/T1 =P2V2/T2,
Here given, P2 = P1 /2 and T2 = 2 T1,
By solving we get V2 = 4 V1.
So, option D is correct.
n and R are constant.
So, PV/T = constant.
So, P1V1/T1 =P2V2/T2,
Here given, P2 = P1 /2 and T2 = 2 T1,
By solving we get V2 = 4 V1.
So, option D is correct.
Thakur ji said:
4 years ago
B is the right answer.
It is mention absolute temperature, so temperature constant.
According to Charl's low PV=constant.
We have half of the pressure, so the Volume is double.
It is mention absolute temperature, so temperature constant.
According to Charl's low PV=constant.
We have half of the pressure, so the Volume is double.
Hemant Singh said:
5 years ago
D is the correct answer.
Solanki Savan said:
5 years ago
Yes, D is the right answer.
Pranav Rana said:
6 years ago
@Pratibha and @Balaram.
Both are right.
Option D is the right answer.
Both are right.
Option D is the right answer.
Balaram said:
6 years ago
The correct Answer is [D].
Pratibha said:
7 years ago
Option D is correct.
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