Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 2 (Q.No. 18)
18.
The hydroxyl ion (OH-) concentration in a solution having pH value 3 will be
Discussion:
2 comments Page 1 of 1.
Gurujii said:
2 years ago
pH + pOH = 14.
( pH = 3),
So, pOH = 14-pH,
= 14-3,
= 11.
( pH = 3),
So, pOH = 14-pH,
= 14-3,
= 11.
TANMAY SHAH said:
3 years ago
pH + pOH = 14.
Here pH is 3, so pOH = 11.
Now, pOH = -LOG[OH],
11 = -LOG[OH].
Therefore, LOG[OH] = -11,
So, OH = 10^-11.
Here pH is 3, so pOH = 11.
Now, pOH = -LOG[OH],
11 = -LOG[OH].
Therefore, LOG[OH] = -11,
So, OH = 10^-11.
(2)
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