Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 6 (Q.No. 47)
47.
A compound was found having nitrogen and oxygen in the ratio 28 gm and 80 gm respectively. The formula of the compound is
Discussion:
1 comments Page 1 of 1.
TANMAY SHAH said:
2 years ago
Mass = M.W. * Moles.
For N, 28 = 14 * Moles.
Therefore, Moles of N = 2.
For O, 80 = 16 * Moles.
Therefore, Moles of O = 5.
So, the answer is N2O5.
For N, 28 = 14 * Moles.
Therefore, Moles of N = 2.
For O, 80 = 16 * Moles.
Therefore, Moles of O = 5.
So, the answer is N2O5.
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