Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 1 (Q.No. 38)
38.
6 gms of magnesium (atomic weight = 24), reacts with excess of an acid, the amount of H2 produced will be __________ gm.
Discussion:
3 comments Page 1 of 1.
Friend said:
1 decade ago
No.of moles of magnesium = 6/24 = 0.25 moles.
Reaction: 0.25Mg + 0.5Hcl ...........> 0.25H2 + 0.25Mgcl2.
No.of moles of H2 is 0.25moles.
No.of moles of H2 = weight of H2/molecular weight of H2.
0.25 = ?/2.
Weight of H2 is 0.25*2 = 0.5gm.
Reaction: 0.25Mg + 0.5Hcl ...........> 0.25H2 + 0.25Mgcl2.
No.of moles of H2 is 0.25moles.
No.of moles of H2 = weight of H2/molecular weight of H2.
0.25 = ?/2.
Weight of H2 is 0.25*2 = 0.5gm.
(2)
Ankita Davane said:
9 years ago
Reaction: Mg + H2SO4 -> MgSO4 + H2.
Mol wt of Mg = 24,
Mol wt of H2 = 2,
24 gm of Mg = 2 gm of H2,
6 gm of Mg = ?,
Weight of H2 = (6 * 2)/24 = 0.5 gm.
Mol wt of Mg = 24,
Mol wt of H2 = 2,
24 gm of Mg = 2 gm of H2,
6 gm of Mg = ?,
Weight of H2 = (6 * 2)/24 = 0.5 gm.
(1)
Ajay said:
7 years ago
Mg+H2So4 ->MgSo4+H2.
Mol wt. Of Mg=24,
Mol wt of H2=2,
6 gm of mg= 2/24,
1 gm of mg= 2*6/24,
H2 Produced :- 0.5.
Mol wt. Of Mg=24,
Mol wt of H2=2,
6 gm of mg= 2/24,
1 gm of mg= 2*6/24,
H2 Produced :- 0.5.
(1)
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