Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 3 (Q.No. 35)
35.
The amount of Zn (atomic weight = 65) required to form 224 c.c. of H2 at N.T.P. on treatment with dilute H2SO4 will be __________ gm.
Discussion:
1 comments Page 1 of 1.
Shethjay said:
6 years ago
Zn reacts with H2SO4 according to the following formula:
Zn + H2SO4 ----> ZnSO4 + H2.
Therefore;
-->1 mole of Zn react to give 1 mole of Hydrogen.
-->Volume to 1 mole of Hydrogen is 22400 c.c.
-->1 mole of Zn is 65 gm.
So,
65 gm Zn reacts then gives 22400 c.c. H2.
For 224 c.c. H2 how much Zn required.
= {224*65}÷{22400}.
= 0.65.
Zn + H2SO4 ----> ZnSO4 + H2.
Therefore;
-->1 mole of Zn react to give 1 mole of Hydrogen.
-->Volume to 1 mole of Hydrogen is 22400 c.c.
-->1 mole of Zn is 65 gm.
So,
65 gm Zn reacts then gives 22400 c.c. H2.
For 224 c.c. H2 how much Zn required.
= {224*65}÷{22400}.
= 0.65.
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