Chemical Engineering - Stoichiometry - Discussion

Discussion Forum : Stoichiometry - Section 4 (Q.No. 38)
38.
How much O2 can be obtained from 90 kg of water ?
32 kg
80 kg
64 kg
90 kg
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

MFquy said:   9 years ago
Please give me the procedure.

Kaushik said:   9 years ago
Please explain the answer.

Dilip kumar kushwaha said:   8 years ago
Please explain the answer.

Pradeep Pal said:   8 years ago
Please explain the answer clearly.

Sanat Shukla said:   8 years ago
H2+1/2O2=H2O.
2+32/2=18.

18H2O=08O2,
So,
90H2O=16/18*90. O2.
O2= 16*5 =80 kg O2.

Dilip kumar kushwaha said:   7 years ago
I am not getting it, please explain the answer.

Sonu said:   7 years ago
(16/18) * 90 = 80.

Sohail said:   4 years ago
H2+1/2O2---> H2O.

2+1/2 * 32=18.

Now taking
H2O:O2,
18:16,
1:16/18,
90:16/18 * 90,
= 80.

Naveen said:   3 years ago
H2+2O2 = 2H20.

90 grams of water = 5 moles of water (moles=weight/molecular weight)

That means 2 moles of O2 = 2 moles of H2o,
?moles of O2 = 5 moles of H2O,
5x2÷2 = 5 moles.
Convert moles of O2 to the weight of O2 get 80 gms.

TANMAY SHAH said:   2 years ago
2H2 + O2 = 2H2O.

So, we can say that 1 mole of O2 gives 2 moles of H2O.

Now from the formula,
Mass = M.W. × Moles
We can get 90 kg [90000 gm] of H2O containing 5000 no. of moles.

Now, 2 moles H2O = 1 mole O2.
5000 moles H2O= ?
So, we get 2500 moles of O2.

Now by converting moles into mass we get 80000 gm or 80 kg of O2.


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