# Chemical Engineering - Stoichiometry - Discussion

### Discussion :: Stoichiometry - Section 1 (Q.No.1)

1.

CaCO3 contains __________ percent of Ca by weight.

 [A]. 40 [B]. 48 [C]. 96 [D]. 12

Explanation:

No answer description available for this question.

 Kamesh said: (May 17, 2012) Ca mw=40 CaCO3 mw=100 Therefore 40/100=40%

 Rahat Ali said: (Jul 4, 2013) As we have to calculate the percentage of "Ca" in CaCO3. for that we have the formula for finding out the percentage, which is: Percentage = Atomic Mass in Gram/Molecular Mass x 100. Putting values.. Percent = 40/100 x 100. = 40% answer.

 Uthman Shalele said: (Dec 21, 2014) Please, I need an answer. Analysis of a carefully purified sample give C = 40%, H = 50%, O = 54%. The mole mass was found to be 180 determine.

 Sriram said: (Apr 15, 2015) Molecular weight of calcium is 40.

 Harshpanchal said: (Jul 19, 2015) mw of ca = 40. Then caco3 = 100. So 40/100 = 40%.

 Yogesh R said: (Jun 12, 2019) The molecular weight of CaCO3 = 100. The atomic weight of ca =40, Percentage of ca in caco3 = (40รท100) * 100, =40.

 Avneesh Rathor said: (Aug 19, 2019) Let Mw of caco3 = 100, Awof ca = 40, Percentageof ca incaco3 = 40%100 * 100.

 Prachiti Deshpande said: (Feb 15, 2022) Here Molecular weight of Ca = 40. Also Molecular weight of CaCO3 = 40 + 12 +1 6*3 = 100. Percentage of CA in CaCO3 = 40/100= 40%.