Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 3 (Q.No. 16)
16.
The number of H+ in 1 c.c solution of pH 13 is
Discussion:
2 comments Page 1 of 1.
Aamir said:
7 years ago
Since pH = -log10[H+],
then [H+] = 10^-pH,
So [H+] = 10^-13 moles/litre,
1 c.c= 1 * 10^-3 l.
And since Avogadro's number = 6.022 * 10^23 we can calculate the number of H+ ions as:
1 * 10^-13 * 1 * 10^-3 * 6.022 * 10^23 = 6.022 * 10^7 ions.
then [H+] = 10^-pH,
So [H+] = 10^-13 moles/litre,
1 c.c= 1 * 10^-3 l.
And since Avogadro's number = 6.022 * 10^23 we can calculate the number of H+ ions as:
1 * 10^-13 * 1 * 10^-3 * 6.022 * 10^23 = 6.022 * 10^7 ions.
TANMAY SHAH said:
3 years ago
pH = -log [H+]
log [H+] = -pH = -13
H+ = 10^-13 moles/litre.
Now, 1 litre = 10^3 c.c.
So, H+ = 10^-16 moles/c.c.
Now, Avogadro's number=6.023 * 10^23 moles^-1
So,
H+ = 10^-16 * 6.023 * 10^23,
= 6.023 * 10^7.
log [H+] = -pH = -13
H+ = 10^-13 moles/litre.
Now, 1 litre = 10^3 c.c.
So, H+ = 10^-16 moles/c.c.
Now, Avogadro's number=6.023 * 10^23 moles^-1
So,
H+ = 10^-16 * 6.023 * 10^23,
= 6.023 * 10^7.
(1)
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