Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 2 (Q.No. 46)
46.
40 gms each of the methane and oxygen are mixed in an empty container maintained at 40°C. The fraction of the total pressure exerted by oxygen is
Discussion:
2 comments Page 1 of 1.
HANADI said:
8 years ago
NO MOLS OF O2=W/32,
NO OF MOLS CH4=W/16,
TOTAL NO OF MOLS =W/23+W/16=3W/32,
MOLE FRACTION = NO OF MOLS COMPONENT/TOTAL MOLS.
=W/32/3W/32,
=1/3.
NO OF MOLS CH4=W/16,
TOTAL NO OF MOLS =W/23+W/16=3W/32,
MOLE FRACTION = NO OF MOLS COMPONENT/TOTAL MOLS.
=W/32/3W/32,
=1/3.
Hanadi said:
8 years ago
Mole of o2=40/32,
=1.25.
mols of ch4=40/16.
=2.5.
mole fraction of o2= 1.25/(1.25+2.5),
=0.3,
=1/3.
=1.25.
mols of ch4=40/16.
=2.5.
mole fraction of o2= 1.25/(1.25+2.5),
=0.3,
=1/3.
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