Chemical Engineering - Process Equipment and Plant Design - Discussion
Discussion Forum : Process Equipment and Plant Design - Section 4 (Q.No. 8)
8.
Tube side heat transfer co-efficient for turbulent flow of liquid through tubes is proportional to
Discussion:
2 comments Page 1 of 1.
Jitu said:
7 years ago
Heat transfer co-efficient, hG(Kcal/hr.m2 .°C) and mass velocity of air, G (kg/hr.m2 ) for air flow parallel to the surface in case of constant drying rate in batch drying is related as hG = 0.0176G^0.8. But when the flow of air perpendicular to the surface is encountered, this equation changes to hG = 1.004G^0.37.
JAYRANJAN said:
9 years ago
For turbulent flow:
Nu = 0.23 Re^0.8 x Pr^0.3.
(hd/k) = 0.23 (density x velocity/viscosity)^0.8 x (viscosity x specific heat/k).
h proportional to velocity^0.8.
h proportional to G^0.8.
Nu = 0.23 Re^0.8 x Pr^0.3.
(hd/k) = 0.23 (density x velocity/viscosity)^0.8 x (viscosity x specific heat/k).
h proportional to velocity^0.8.
h proportional to G^0.8.
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