Chemical Engineering - Nuclear Power Engineering - Discussion
Discussion Forum : Nuclear Power Engineering - Section 1 (Q.No. 7)
7.
The amount of a radioactive material (having a half life of 100 years) remaining after 400 years will be __________ of its original weight.
Discussion:
2 comments Page 1 of 1.
Rots said:
9 years ago
0.5 + 0.25 + 0.125 + 0.0625 = 0.9375.
1 - 0.9375 = 1/16.
1 - 0.9375 = 1/16.
Shafeeque said:
9 years ago
100y = 1/2,
200y = 1/2 * 1/2,
400y = 1/4 * 1/4 = 1/16.
200y = 1/2 * 1/2,
400y = 1/4 * 1/4 = 1/16.
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