Chemical Engineering - Mechanical Operations - Discussion

Discussion Forum : Mechanical Operations - Section 8 (Q.No. 14)
14.
A 30% (by volume) suspension of spherical sand particles in a viscous oil has a hindered settling velocity of 4.44 μm/s. If the Richardson Zaki hindered settling index is 4.5, then the terminal velocity of a sand grain is
0.90 μm/s
1 μm/s
22.1 μm/s
0.02 μm/s
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

BLLover said:   12 months ago
B is wrong.

In hindered settling, Richardson and Zaki (1954) performed sedimentation experiments to determine values for the hindered settling index in the equation

v_p = v_T*ε^n

where:
v_p = particle velocity
v_T = terminal velocity of the particle
ε = porosity
n = hindered settling index

Plugging in the values given would give a v_T of 22.1 μm/s.

Hemant said:   5 years ago
The answer should be C 22.1μs.
(3)

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