Chemical Engineering - Mechanical Operations - Discussion
Discussion Forum : Mechanical Operations - Section 1 (Q.No. 3)
3.
If dp is the equivalent diameter of a non-spherical particle, Vp its volume and sp its surface area, then its sphericity is Φs is defined by
Discussion:
2 comments Page 1 of 1.
Ayushi Soni said:
6 years ago
Volume of sphere= 1/6*π *d^3.
Surface area of sphere=π *d^2.
Then;
Volume to surface ratio of sphere =dp/6.
Since;
Sphericity = vol/surface ratio of any partial divided by vol/surface ratio of the sphere.
Hence:
φs= (Vp/Sp)/(dp/6).
= 6Vp/dp*Sp.
Surface area of sphere=π *d^2.
Then;
Volume to surface ratio of sphere =dp/6.
Since;
Sphericity = vol/surface ratio of any partial divided by vol/surface ratio of the sphere.
Hence:
φs= (Vp/Sp)/(dp/6).
= 6Vp/dp*Sp.
(1)
Vivek said:
9 years ago
Good answer. Can you explain it?
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