Chemical Engineering - Mechanical Operations - Discussion
Discussion Forum : Mechanical Operations - Section 1 (Q.No. 36)
36.
The energy required per unit mass to grind limestone particles of very large size to 100 μm is 12.7 kWh/ton. An estimate (using Bond's law) of the energy to grind the particles from a very large size to 50 μrn is
Discussion:
2 comments Page 1 of 1.
Rohan said:
1 decade ago
Bond's law:
P/m = Kb/(Dp)^0.5.
Dp is in mm.
For 100 micrometer i.e. 100*10^-3 mm.
12.7 = Kb/(100*10^-3)^0. 5.
Kb = 4.016.
For 50 micrometer i.e. 50*10^-3 mm.
P/m = 4.016/(50*10^-3)^0.5.
P/m = 17.96 Kwh/ton.
P/m = Kb/(Dp)^0.5.
Dp is in mm.
For 100 micrometer i.e. 100*10^-3 mm.
12.7 = Kb/(100*10^-3)^0. 5.
Kb = 4.016.
For 50 micrometer i.e. 50*10^-3 mm.
P/m = 4.016/(50*10^-3)^0.5.
P/m = 17.96 Kwh/ton.
(16)
Solanki Savan said:
5 years ago
Right, Thanks @Rohan.
(2)
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