Chemical Engineering - Mechanical Operations - Discussion
Discussion Forum : Mechanical Operations - Section 9 (Q.No. 56)
56.
What is the reduction ratio in a fine crushing operation having following feed and product sizes?
Discussion:
2 comments Page 1 of 1.
Ram Ram said:
2 years ago
Feed material/products.
= 20 × 10/10 × 10.
=2 is the correct answer.
= 20 × 10/10 × 10.
=2 is the correct answer.
Varsha katta said:
8 months ago
For maximum particle size, the reduction ratio is given by;
R.r = feed size/product size , 20/10 = 2.
For minimum particle size, the reduction ratio is given by
10/5 = 2.
Since, the correct answer is 2.
R.r = feed size/product size , 20/10 = 2.
For minimum particle size, the reduction ratio is given by
10/5 = 2.
Since, the correct answer is 2.
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