Chemical Engineering - Mass Transfer - Discussion
Discussion Forum : Mass Transfer - Section 2 (Q.No. 18)
18.
Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit is
Discussion:
5 comments Page 1 of 1.
Ram said:
5 years ago
400 mol of S ------------------>400mol of S+x mole of A.
200 mol of B+a mol of A----->200mol of B +(a-x) mol of A.
Given y = 3x^2.
(a-x)/200 = 3(x/400)^2.
a-x =(3/800)*2.
The maximum percentage of extraction can be achieved.
When a - x = x or a = 2x.
Maximum extraction=x/a=x/2x=0.5.
= 50%.
200 mol of B+a mol of A----->200mol of B +(a-x) mol of A.
Given y = 3x^2.
(a-x)/200 = 3(x/400)^2.
a-x =(3/800)*2.
The maximum percentage of extraction can be achieved.
When a - x = x or a = 2x.
Maximum extraction=x/a=x/2x=0.5.
= 50%.
(3)
Enass said:
5 years ago
What is the anwer.
Lulseged cherihun said:
6 years ago
Good but explain with the calculation for the next questions.
Ashraf said:
8 years ago
Why? Explain.
(1)
Ahmed said:
1 decade ago
Could any one explain why, please?
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