Chemical Engineering - Mass Transfer - Discussion

D. P. Proportional pressure.

So, both C&D is correct.

Since, the dew point is directly proportional to the pressure, so both the option C&D is correct.

I think Both C &D will be Correct.

Both C ad D correct.

As pressure increases dew point increases as pressure decreases dew point decreases.

Compression and expansion of air affect its dew point. Generally speaking, compression increases dew point, and expansion (i.e De-compression) lowers dew point. For example, consider compressed air leaving a dryer at 200 PSIG with a pressure dew point of -40° F/C at 200 psig. If the pressure is eventually reduced to 100 psig, the pressure dew point will fall to -50 °F at 100 psig. If the air is further expanded to 5 psig, the pressure dew point becomes -77° F at 5 psig.

Answer is D correct.

I think both C and D are correct.

I think both A and C is right.

At dew point vapour convert in liquid by using latent heat at constant temp according to latent haet definition.

Assume we have pot in this pot some vapours are present if pressure increase in this pot vapour will be condensed but in another condition, we have liquid in pot at constant volume let 2 atm pressure on it if we decrease pressure then the B P will decrease in liquid is flashed and more vapours will be formed so and vapour molecules loss it's energy and get cooled and after that condensed and d p will be increased.

C is correct. Agree with the given answer.

Dew point is independent of temperature and directly proportional of pressure so C and D both option is correct.