Chemical Engineering - Mass Transfer - Discussion

Discussion Forum : Mass Transfer - Section 9 (Q.No. 12)
12.
The reflux to a distillation column is 100 moles/hr, when the overhead product rate is 50 moles/hr. The reflux ratio is
2
0.5
50
150
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
4 comments Page 1 of 1.

Adnan Ahmad Khattak said:   4 years ago
The Reflux ratio is basically R = L/D.
L = reflux,
D = distillate,
Here, L = 100 and D = 50.
So, 2 is the correct answer, mean option A.
(1)

Raj Musale said:   6 years ago
Overhead product means distillate.
L=100 at D=50.
Reflux ratio = L/D=2.

Surjeet said:   1 decade ago
Reflux Ratio = Reflux/Distillate.

= 100/50 = 2.

Neeraj Kumar shakya said:   7 years ago
Reflux ratio = L/D.
= 50/100 = 0.5.

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