Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 10 (Q.No. 8)
8.
The left face of a one dimensional slab of thickness 0.2 m is maintained at 80°C and the right face is exposed to air at 30°C. The thermal conductivity of the slab is 1.2 W/m.K and the heat transfer co-efficient from the right face is 10 W/m2.K. At steady state, the temperature of the right face in °C is
Discussion:
2 comments Page 1 of 1.
Wisam alkinany said:
4 years ago
Qcond.=Qconv.
hA.(T right - T air) = kA dt/dx.
10 (T right - 30+273) = 1.2/0.2 (80+ 373 - T right).
Tright = 48.75.
hA.(T right - T air) = kA dt/dx.
10 (T right - 30+273) = 1.2/0.2 (80+ 373 - T right).
Tright = 48.75.
(1)
Ezaz Ahmed said:
1 decade ago
Q= hA(T1-T2).
Q = kAdt/dx.
kAdt/dx = hA(t1-T2).
Area cancelled.
Put values answer = 48.75.
Q = kAdt/dx.
kAdt/dx = hA(t1-T2).
Area cancelled.
Put values answer = 48.75.
(1)
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