Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 3 (Q.No. 47)
47.
A fluid is flowing inside the inner tube of a double pipe heat exchanger with diameter 'd'. For a fixed mass flow rate, the tube side heat transfer co-efficient for turbulent flow conditions is proportional to
Discussion:
5 comments Page 1 of 1.
Sujit P said:
4 years ago
For turbulent for we use Dittus-Bölter correlation.
h*d/K = 0.23 * 9(j*d/u)^0.8)*(u*Cp/k)^n.
Now take d from LHS to RHS we find h is proportional to d^-0.2.
So, B is right.
h*d/K = 0.23 * 9(j*d/u)^0.8)*(u*Cp/k)^n.
Now take d from LHS to RHS we find h is proportional to d^-0.2.
So, B is right.
(1)
Y Eswar said:
5 years ago
D is the right answer.
(1)
VjayS said:
7 years ago
For fully turbulent condition, hd/k = 0.048 * {Re}^.8.
Anonymous said:
7 years ago
According to me, the answer should be the d^-1.6.
Gautam said:
8 years ago
Answer D is right.
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