Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 7 (Q.No. 20)
20.
At steady state the temperature variation in a plane wall, made of two different solids I & II is shown below :
The thermal conductivity of material I
The thermal conductivity of material I
Discussion:
3 comments Page 1 of 1.
Alpesh Solanki said:
9 years ago
Temperature difference is inversely proportional to thermal conductivity by equation;
(T - t) = qx/kA.
x = thickness.
k = thermal conductivity.
A = area.
q = rate of heat transfer.
Thus, the temp drop is higher in 1st plane.
(T - t) = qx/kA.
x = thickness.
k = thermal conductivity.
A = area.
q = rate of heat transfer.
Thus, the temp drop is higher in 1st plane.
Philip said:
8 years ago
It can be noticed from the graph that the slope of the 1st material is steeper than the second, so heat transfer from the first should be faster, thus, the thermal conductivity.
(4)
Philip said:
8 years ago
There should be a relationship stated between the temperature gradient of material 1 to material 2 otherwise, we can't say anything about which one has larger conductivity.
(2)
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