Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 10 (Q.No. 38)
38.
For turbulent flow in a tube, the heat transfer co-efficient is obtained from the Dittus-Boelter correlation. If the tube diameter is halved and the flow rate is doubled, then the heat transfer co-efficient will change by a factor of
Discussion:
3 comments Page 1 of 1.
Ankur said:
1 decade ago
Q = A*V.
A proportional to D^2.. as D reduce to 0.5 then A reduce to 0.25.
But Q increase to 2.
For that velocity increase to 8.
Hence, Increase h= 8^0.8 * 0.5^-0.2 = 6.1.
A proportional to D^2.. as D reduce to 0.5 then A reduce to 0.25.
But Q increase to 2.
For that velocity increase to 8.
Hence, Increase h= 8^0.8 * 0.5^-0.2 = 6.1.
(1)
Ritesh said:
7 years ago
@Ankur.
Here heat transfer Co-efficient is asked, not about volumetric flow rate.
Here heat transfer Co-efficient is asked, not about volumetric flow rate.
Chayanika said:
6 months ago
How it will be 6.1? Please explain to me.
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