Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 8 (Q.No. 42)
42.
The Sieder-Tate correlation for heat transfer in turbulent flow in pipe gives Nu α Re0.8, where, Nu is the Nusselt number and Re is the Reynolds number for the flow. Assuming that this relation is valid, the heat transfer co-efficient varies with the pipe diameter (D) as
Discussion:
2 comments Page 1 of 1.
Ani said:
7 years ago
Q = v*A.
Q/A = v.
Nu=(v*d/Viscosity)^0.8.
hd/k=(Q/D^2/4*D)^0.8,
h = (4Q/D)^0.8/D,
h = k*D^-1.8.
Q/A = v.
Nu=(v*d/Viscosity)^0.8.
hd/k=(Q/D^2/4*D)^0.8,
h = (4Q/D)^0.8/D,
h = k*D^-1.8.
Mnnit said:
6 years ago
The correct answer is B.
Simply use=hD/k=(density*v*D/viscosity)^0.8.
Simply use=hD/k=(density*v*D/viscosity)^0.8.
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