Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 2 (Q.No. 22)
22.
The thermal radiation emitted by a body is proportional to Tn, where T is its absolute temperature. The value of 'n' is exactly 4 for
Discussion:
11 comments Page 1 of 2.
TANMAY SHAH said:
2 years ago
I also think Option-D is the Right answer.
Rahul Maurya said:
3 years ago
Yes, I too agree, D is the right answer.
RAJKUMAR PEGU said:
3 years ago
Here the answer is correct. Because Emissive power for black body = (σ) *T^4.
But for non-black bodies Emissive power = (emissivity) * (σ) *T^4, so the power of 'T' is always 4 for anybody.
But for non-black bodies Emissive power = (emissivity) * (σ) *T^4, so the power of 'T' is always 4 for anybody.
(4)
Radhe said:
4 years ago
For all bodies, it is 4 only. Only an emissivity factor is multiplied with T^4 to get the Q.
Raveendra said:
4 years ago
Option D is the correct answer.
Fardin Zindran said:
5 years ago
Answer is D. According to Stefan Boltzman Law.
Arun said:
6 years ago
What about all bodies? Please explain in detail.
Sreejith said:
7 years ago
The Stefan"Boltzmann law describes the power radiated from a black body in terms of its temperature. Specifically, the Stefan"Boltzmann law states that the total energy radiated per unit surface area of a black body across all wavelengths per unit time (also known as the black-body radiant emittance) is directly proportional to the fourth power of the black body's thermodynamic temperature T.
Nithin said:
7 years ago
D is the correct answer.
Ram said:
8 years ago
I think D answer is right.
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