Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 4 (Q.No. 18)
18.
In a parallel flow heat exchanger, if the outlet temperature of hot and cold fluids are the same, then the log mean temperature difference (LMTD) is
Discussion:
4 comments Page 1 of 1.
Ajay Ramani said:
8 years ago
Lmtd= (dt1 - dt2)/{ln(dt1/dt2)}.
Here, dt2=0 soh the denominator approaches to INFINITY value. Hence results in ZERO.
Here, dt2=0 soh the denominator approaches to INFINITY value. Hence results in ZERO.
(1)
Suraj said:
9 years ago
It is very simple, consider the formula of LMTD.
Afjal said:
10 months ago
I think the answer should be infinity.
SUMIT said:
8 years ago
How Zero?
Explain in detail.
Explain in detail.
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