Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 2 (Q.No. 20)
20.
The Nusselt number for fully developed (both thermally and hydrodynamically) laminar flow through a circular pipe, where the wall heat flux is constant, is
Discussion:
6 comments Page 1 of 1.
SONU MAURYA said:
5 years ago
(Nu), for constant wall heat flux and (Nu)t at constant wall temperature for a hydrodynamically and thermally fully developed laminar flow through a circular pipe of the constant cross-section is 4.36 and 3.66 respectively. Hence, (Nu), > (Nu)T.
Bajwa said:
1 decade ago
@Mr. Mahesh.
Please correct your answer Nusselt number for fully developed laminar flow through a round pipe is,
Nu = 3.66 for isothermal pipe (Ts = constant).
Nu = 3.36 for constant heat flux pipe.
Please correct your answer Nusselt number for fully developed laminar flow through a round pipe is,
Nu = 3.66 for isothermal pipe (Ts = constant).
Nu = 3.36 for constant heat flux pipe.
Mahesh konduri said:
1 decade ago
The Nusselt number for fully developed (both thermally and hydrodynamically) laminar flow through a circular pipe,
Nu = 3.66 for constant heat flux.
Nu = 4.36 for constant wall temperature.
Nu = 3.66 for constant heat flux.
Nu = 4.36 for constant wall temperature.
(1)
Zhang zhao said:
3 months ago
For a uniform wall temperature:
NuD = 3.66.
For a uniform heat flux through the tube wall:
NuD = 4.36.
NuD = 3.66.
For a uniform heat flux through the tube wall:
NuD = 4.36.
Naveen Solanki said:
6 years ago
The Correct answer:
For constant heat flux, Nu = 4.36.
For constant surface temp, Nu = 3.66.
For constant heat flux, Nu = 4.36.
For constant surface temp, Nu = 3.66.
(3)
Rana Rohan said:
6 years ago
Thanks @Naveen Solanki.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers