Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 2 (Q.No. 14)
14.
Resistance to heat flow by conduction is proportional to (where, t & ρ are thickness & density of the material respectively and A = area normal to the direction of heat flow. )
Discussion:
5 comments Page 1 of 1.
ALPESH SOLANKI said:
5 years ago
Resistance to heat flow by CONDUCTION is proportional to ΔT,A,1/density.
because q=mcΔt.
m=v*density.
and q is inversely proportional to the resistance.
because q=mcΔt.
m=v*density.
and q is inversely proportional to the resistance.
Ajay said:
4 years ago
Resistance for conduction.
R = x/kA.
Where R (resistance), x (thickness of wall material), k (thermal conductivity), A( Area).
R = x/kA.
Where R (resistance), x (thickness of wall material), k (thermal conductivity), A( Area).
Deekshant said:
1 decade ago
q = (t1-t2)/R;
q = mCp(ti-t2).
So R = 1/mCp.
And m=density*volumetricflow rate.
q = hA(t1-t2).
R = 1/hA.
q = mCp(ti-t2).
So R = 1/mCp.
And m=density*volumetricflow rate.
q = hA(t1-t2).
R = 1/hA.
Ankita said:
7 years ago
@Deekshant.
q = hA (t1-t2) is for convection not conduction.
q = hA (t1-t2) is for convection not conduction.
Divaldee said:
7 years ago
Is it calculated using q=-kA.dx/dt?
Please tell me.
Please tell me.
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