Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 3 (Q.No. 12)
12.
In a liquid-liquid heat exchanger, for the same process temperature, the ratio of the LMTD in parallel flow to the LMTD in counter flow is always
Discussion:
7 comments Page 1 of 1.
Ananthu u said:
2 years ago
The right answer is option A. Because limited for the counter is larger. While we take the ratio of parallel to counter current we always get the value < 1. If they are asking the ratio of counter to parallel then only the answer becomes > 1.
Harsh said:
7 years ago
Yes, right @Sravani.
According to Q=U*A*Δ (Tm). Here U is inversely proportional to Tm. U for countercurrent is always greater then Co-current. So the answer should be greater than 1.
According to Q=U*A*Δ (Tm). Here U is inversely proportional to Tm. U for countercurrent is always greater then Co-current. So the answer should be greater than 1.
TANMAY SHAH said:
2 years ago
LMTD for counter flow heat exchangers is always greater than the LMTD for parallel flow heat exchangers.
Maha said:
4 years ago
The correct option is B.
LMTD ratio in parallel flow to counter flow is greater than 1.
LMTD ratio in parallel flow to counter flow is greater than 1.
Sravani said:
7 years ago
But here they are considering the ratio of parallel to counterflow.
Rishu said:
10 years ago
LMTD for parallel is more as compared to counter flow.
Ramana said:
8 years ago
Yes. lmtd for parallel is more than counter.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers