Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 2 (Q.No. 17)
17.
Three piping networks as shown in the figure are placed horizontally. They are made using identical pipe segments and are subjected to the same pressure drop across them. Assuming no pressure losses at junctions, the flow rates across the three networks are related as Q1 : Q2 : Q3.
Discussion:
5 comments Page 1 of 1.
Ashish patel said:
7 years ago
Now apply a formula √p/L =4fLV^2/2D.....now put a flowrate Q=VA and you will Get a relationship between flow rate and pressure drop.As pressure drop should remain constant and also there is no loss at junction.
So finally √p proportional to (Q)^2 and proceed so on.
So finally √p proportional to (Q)^2 and proceed so on.
Shravani said:
7 years ago
This can be seen as an equivalent to an electric circuit where the pressure drop is the driving force (potential difference V), each identical pipe is a resistor of resistance R and the flow rate Q is the current I in the circuit.
I1= V/2R , I2 = V/ R, I3 = V/ R (in third case, we apply the wheatstone bridge)
So Q1: Q2: Q3 = 1/2 : 1 : 1 = 1:2:2.
I1= V/2R , I2 = V/ R, I3 = V/ R (in third case, we apply the wheatstone bridge)
So Q1: Q2: Q3 = 1/2 : 1 : 1 = 1:2:2.
(1)
TansaJhankali said:
8 years ago
Please explain this answer.
Peter said:
8 years ago
Can Anyone explain how this came?
Ronnie said:
8 years ago
Describe the action of atmospheric pressure on force pump.
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