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Chemical Engineering - Fluid Mechanics - Discussion

Discussion Forum : Fluid Mechanics - Section 5 (Q.No. 48)
Fluid Mechanics
48.
For the manometer set up shown in the figure, the pressure difference PA - PB is given by
(ρH - ρair)gH
(ρH - ρL)gH
(ρH - ρL) gH + (ρL - ρair) . g(L - H)
(ρH - ρL) gL + (ρL - ρair)gH
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
1 comments Page 1 of 1.
Sirius Rankine said:   3 years ago
PA + ρair H g + ρL L g = PB + ρL L g + ρH H g.

=> PA - PB = (ρH - ρair)Hg.
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