Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 4 (Q.No. 18)
18.
For turbulent flow of an incompressible fluid through a pipe, the flow rate Q is proportional to (Δ P)n, where ΔP is the pressure drop. The value of exponent 'n' is
Discussion:
2 comments Page 1 of 1.
Makwana Yogesh said:
1 month ago
The correct answer is: > 1.
Explanation:
For turbulent flow of an incompressible fluid through a pipe, the relationship between the pressure drop (ΔP) and the flow rate (Q) is non-linear and follows a power-law behaviour:
Q proportional to (Δ P)^n.
In laminar flow, ⇒ In turbulent flow, due to increased friction and eddies, the relationship becomes nonlinear, and n > 1.
Typically, for fully developed turbulent flow, n ≈ 1.75, as in the Blasius correlation for smooth pipes.
Therefore, the correct answer is: > 1.
Explanation:
For turbulent flow of an incompressible fluid through a pipe, the relationship between the pressure drop (ΔP) and the flow rate (Q) is non-linear and follows a power-law behaviour:
Q proportional to (Δ P)^n.
In laminar flow, ⇒ In turbulent flow, due to increased friction and eddies, the relationship becomes nonlinear, and n > 1.
Typically, for fully developed turbulent flow, n ≈ 1.75, as in the Blasius correlation for smooth pipes.
Therefore, the correct answer is: > 1.
Ravi said:
1 decade ago
Change in pressure = 4*f*Q^2/A^2.D;
HENCE Q PROPORTIONAL TO (CHANGE IN PRESSURE)^.5;
So n<1.
HENCE Q PROPORTIONAL TO (CHANGE IN PRESSURE)^.5;
So n<1.
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