Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 11 (Q.No. 29)
29.
A free jet of water of cross-sectional area 0.01m2 and a velocity of 20 m/s strikes a plate and then flows in a plane parallel to the plate as shown in the figure below. The horizontal component of the force on the support is
Discussion:
1 comments Page 1 of 1.
Venkat said:
7 years ago
Force = density of fluid * c/s area of pipe * velocity^2.
Force = 1000*0.01*20^2 = 4000N.
Force = 1000*0.01*20^2 = 4000N.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers