Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 10 (Q.No. 26)
26.
Water is flowing at 1 m/sec through a pipe (of 10 cm I.D) with a right angle bend. The force in Newtons exerted on the bend by water is
Discussion:
3 comments Page 1 of 1.
Ramesh vanapalli said:
7 years ago
F= ρ *u^2*a*sin∠.
a=area, u=velocity, ∠'=angle, rho=density. Submit the values in the above formula you will get the answer.
a=area, u=velocity, ∠'=angle, rho=density. Submit the values in the above formula you will get the answer.
(2)
Suri said:
6 years ago
F= density * velocity * area .
= 1000 * 1 * 0.0078.
= 7.85.
= 1000 * 1 * 0.0078.
= 7.85.
Rana said:
5 years ago
Right, Thanks @Ramesh Vanapalli.
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