Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 14 (Q.No. 45)
45.
A 0.5 m high bed made up of a 1 mm dia glass sphere (density 2500 kg/m3 ) is to be fluidised by water (density 1000 kg/m3 ). If at the point of incipient fluidisation, the bed voidage is 40%, the pressure drop across the bed is
Discussion:
1 comments Page 1 of 1.
KREL said:
10 months ago
Incipient fluidization is when the particles just begin to lift.
Pressure drop per unit bed height in a fluidized bed is given by: -ΔP/L = (1-ε)*(ρ_p-ρ)*g.
Therefore:
-ΔP = L*(1-ε)*(ρp-ρ)*g.
= 0.5 * (1 - 0.4) * (2500 - 1000) * 9.81,
= 4414.5 Pa or 4.4 kPa.
Pressure drop per unit bed height in a fluidized bed is given by: -ΔP/L = (1-ε)*(ρ_p-ρ)*g.
Therefore:
-ΔP = L*(1-ε)*(ρp-ρ)*g.
= 0.5 * (1 - 0.4) * (2500 - 1000) * 9.81,
= 4414.5 Pa or 4.4 kPa.
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