Chemical Engineering - Fluid Mechanics - Discussion

Discussion Forum : Fluid Mechanics - Section 1 (Q.No. 32)
32.
For Laminar flow through a packed bed, the pressure drop is proportional to (Vs is the superficial liquid velocity and Dp is the particle diameter)
Vs/Dp2
Vs2/Dp2
Vs2/Dp3
Vs/Dp3
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

Rajkumar Pegu said:   3 years ago
Superficial liquid velocity is the hypothetical velocity of the liquid if we consider that there only the liquid phase is present in the packed bed column.

MANISH said:   7 years ago
According to Eargen equation, the pressure drop in case of Laminar flow is 150*(1-e)2 *u *v /d2*e3, it shows the pressure drop is a proposal to v/d2.

Dev goswami said:   6 years ago
It's Kozeny Karman equation not Ergun.

Ergun is the sum of laminar and turbulent means sum of Burke Plummer and Kozeny.
(1)

Akshat said:   1 decade ago
By Ergun equation, pressure drop will be proportional to Vs^2Dp.

Rajkumar said:   3 years ago
What is superficial liquid velocity?

Please, anyone explain.
(1)

Prerak said:   8 years ago
Not ergun @Akshat.

It's Carman-Kozeny equation.

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