Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 14 (Q.No. 44)
44.
A rotameter through which air at room temperature and atmospheric pressure is flowing gives a certain reading for a flow rate of 100 cc/sec. If helium (molecular weight 4) is used and rotameter shows the same reading, the flow rate (cc/sec) is
Discussion:
2 comments Page 1 of 1.
RAJ PANDIT said:
4 years ago
Rotameter flowrate is inversely proportional to square root of molecular weight,
So v1/v2 = (M2/M1)^0.5,
So v2 = (M1/M2)^0.5 * v1,
So v2 = (29/4)^0.5 * 100.
So v2 = 269 cc/sec.
So v1/v2 = (M2/M1)^0.5,
So v2 = (M1/M2)^0.5 * v1,
So v2 = (29/4)^0.5 * 100.
So v2 = 269 cc/sec.
(6)
Rana said:
5 years ago
Please explain the answer.
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