Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 14 (Q.No. 34)
34.
Bed pressure drop in an air fluidised bed of catalyst particles (ρp = 200 kg/m3, Dp = 0.05 cm) of 60 cm bed depth and bed porosity of 0.5 expressed in cm of water (manometer) is
Discussion:
1 comments Page 1 of 1.
Amal Abraham said:
2 years ago
h*(10^-2)*ρ*g = (1-E)g(ρp - ρf)l.
h = (0.5 *(2000-1.29)*0.6)/10.
Therefore,
h = 59.998 cm of water.
= 60 cm of water.
h = (0.5 *(2000-1.29)*0.6)/10.
Therefore,
h = 59.998 cm of water.
= 60 cm of water.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers