Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 8 (Q.No. 8)
8.
A Pitot tube indicates 5 cm of water (manometer) when it is being used for measuring velocity of air. The velocity of air in m/sec is
Discussion:
3 comments Page 1 of 1.
Venkat said:
7 years ago
The velocity of fluid u = (2 *(height * density) of manometric fluid * accleration due to gravity / density of fluid(whose velocity is to be measured))^0.5.
u = (2*0.05*1000*9.8/1.225)^0.5,
u = 28.28.
u = (2*0.05*1000*9.8/1.225)^0.5,
u = 28.28.
(2)
Mahendra kumar said:
7 years ago
H in air=H in water[(density of water/density of air) - 1].
So H in air=0.05[(1025/1.225)-1].
H in air=555 m.
The velocity of air = (2 * 9.8 * 555)^0.5.
The Velocity of air = 28.6 m/s.
So H in air=0.05[(1025/1.225)-1].
H in air=555 m.
The velocity of air = (2 * 9.8 * 555)^0.5.
The Velocity of air = 28.6 m/s.
(2)
Mubashir khan said:
3 years ago
Thanks for solving the answer.
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