Chemical Engineering - Fluid Mechanics - Discussion

Discussion Forum : Fluid Mechanics - Section 3 (Q.No. 5)
5.
For a given Reynold number as d/D for an orifice increases, Cd will (where, d & D are orifice & pipe diameters respectively).
increase
decrease
remain constant
either (a) or (b); depends on other factors
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
5 comments Page 1 of 1.

Arindam Roy said:   5 years ago
Reynold's no.=PVD/u(P=density).
Re directly proportional to u,
So if Re increases D will increase and vice versa.
(2)

Anomie said:   4 years ago
What is Cd? Please explain the answer in detail.
(1)

Monisankar Roy said:   2 months ago
Discharge coefficient (Cd) = Bord diameter (d) /Pipe Diameter (D).

Cd increase = d/D also in also increase.

Ashish said:   2 months ago
Q = Cd.Ao(2gh)^1/2 /(1-(d/D)^4) ^1/2.
So, Cd =√1-(d/D)^4.

CD will decrease with increasing d/D.

Ashish said:   2 months ago
For a given Reynolds number, as the ratio of the orifice diameter to the pipe diameter (d/D) increases, the coefficient of discharge (Cd) will decrease.

The coefficient of discharge is the ratio of the actual flow to the ideal flow, and it's always less than one.

The value of Cd depends on several factors, including the Reynolds number, the shape of the nozzle, and the ratio of the pipe to Nozzle diameter.

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